O sinal de menos (-) também pode ser usado para subtrair datas. If you want the difference, then use datediff () or timestampdiff (). select datediff (second, CURRENT_TIMESTAMP, fs. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. DATEDIFF. In Snowflake you can rewrite the query : SELECT datediff (day, '1900-01-01',. snowpark. I will use floating point maths to make my point. Only the date parts of the values are used in the calculation. Supported date and. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. snowflake. In Snowflake you can rewrite the query : SELECT datediff (day, '1900-01-01', CURRENT_DATE); Time Part Extracted from Time / Timestamp. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. Snowflake is cloud agnostic and uses virtual compute instances from each cloud provider (AWS EC2, Azure VM, Google Compute Engine). So this is really two parts, to know what year-quarter something is with respect to an offset, you just need to subtract the offset month, from the date you have and then year and quarter the adjusted date. Go to snowflake r/snowflake • by terminal_bound. SnowflakeのDATEDIFF関数では、指定している単位（今回は「DAY」）の数値のズレを計算するため、BQとは異なる結果が出力される。 そのため、例えば、5月8日の23時39分20秒と日付が変わった瞬間の時刻の差分を計算すると、実際には20分程度しかたっていないにも. Snowflake SQL compilation error: cannot change column from type TIMESTAMP_LTZ(9) to TIMESTAMP_NTZ(9) 2 DateTime in Snowflake Timestamp '23-Jan-2015 23:02:39' is not recognizedMin/Max of a group. The default is month. startdate: The first date or datetime value. 141') -- FAILURE: The datediff function resulted in an overflow. : create temp table dummy_1 (days int) as select datediff ('day', '2018-07-20', '2018-07-27'); 2. The LAG function is getting the second, third, fourth, fifth, sixth and seventh rows of data based upon the udid. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. SELECT datediff (MINUTE,cast ( [EndTime] as datetime),cast ( [StartTime] as datetime)) FROM YourTable WHERE TRY_CONVERT (DATETIME, [EndTime]) IS NOT NULL AND TRY_CONVERT (DATETIME, [StartTime]) IS NOT NULL. functions. g. HOUR / MINUTE / SECOND¶. When specified as a time, then the DATEDIFF function sets the missing date part to 1900-01-01. I've been successful in mysql removing weekend days from a date range using the formula below where @s = start date and @e = end date in the range. I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. JayRizzo. id , sum (datediff (‘second’, -- calculate the max of the two start time (case when t. The DATEDIFF command takes a datepart and returns the difference between two dates or timestamps. SubmittedDate = 2012-02-29 07:02:55. The LAG () function is used to extend the delay or fall behind to perform an action. Then, filter the rows such that report_datetime is fewer than 6 weeks after creation_datetime. I run the following task in Snowflake to see which queries are candidates for inefficiency improvements: select datediff (second,scheduled_time,query_start_time) as second, * from table (information_schema. 2 days, but Snowflake will produce 1 because 2 is 1 more than 1. case when datediff ('MONTH', FISCAL_CUR_YEAR, V_DATE_1) < 0; then datediff ('MONTH', DATEADD (year,-1, FISCAL_CUR_YEAR), V_DATE_1)+ 1;. There are also consideration of different rules for different countries governing how Daylight Savings Time are calculated, and sometimes the rule changes too. Add a comment. SELECT Customer_ID , Day_ID , DATEDIFF (DAY, LAG (Day_ID) OVER (PARTITION BY Customer_ID ORDER BY. . Please try a simpler expression. Concatenation operator: While we were running & repointing our loads into Snowflake we discovered a important difference in how Oracle vs Snowflake concatenation works. Why DATEDIFF() function in Snowflake works differently while getting date difference in weeks. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. Data Superheroes. String concatenation will build '1' + ',' + '27'. SELECT first_action. Solution. So, for example, if today is Monday 2021-06-28, I only want the results from Monday 2021-06-21 to Sunday 2021-06-27. Please check attempt. If you want the difference, then use datediff () or timestampdiff (). date_from) = 1. 21 2 2 bronze badges. 1. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Push out all due dates by one week. I managed to do it: use schema objectname. While I've solved their problem, It came about that I don't actually know what the 0 turns into when used as they were using it. Know everything you need about Snowflake DATEDIFF. later_date, p. For example, If substring ‘cc’ can be replaced by ‘bb’ in the given input string ‘abbab’, then the resultant output will be ‘accab’. approx_percentile_estimate. For example, TRUNC (TO_DATE ('2013-08-05'), 'QUARTER') returns the first date in the third quarter of the year 2013, which is July 1, 2013. HOUR. T. functions. Viewed 11k times. Q&A for work. : you're comparing dates with timestamps, and not whole days), you can. Usage Notes¶. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time,. This uses the row_number window function along with dateadd and generator to increment from a. 5 * FLOOR ((DATEDIFF (day, date_trunc ('quarter', @s), @e)). 1239') returns 1. BR. I asked our Snowflake rep if they could create. DATEDIFF. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. The fact that the function returns an integer number of months both when the days of the month are the same (e. g. I am new to sql language and recently snowflake. Truncation does not remove the month and day; instead it sets them to the earliest date in the specified period. How to get difference betwen these below two dates in snowflake. Expand Post. See the syntax, usage, and examples of this function with various date and time parts. DATETIME. so the inner most part is DATEDIFF(MONTH, 0, GETDATE()) which is the number of months since beginning of time in your DB timeframe, and the current date in months, with 1 is subtracted from, and that many months are added since 0 in DB timeframe, thus DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()) -1, 0) is the begin of the. 1 Answer. For seconds: DATEDIFF (second, LAG (ACTION_DATE) OVER (PARTITION BY users ORDER BY ACTION_DATE), ACTION_DATE ) AS DIFF_SECONDS. 123 seconds, not 1. A função retorna o resultado da subtração do segundo argumento do terceiro argumento. A função retorna o resultado da subtração do segundo argumento do terceiro argumento. Here are some great date functions to round out your toolkit. This system-defined table function enables synthetic row generation. Snowflake does: unit_answer = TRUNC( unit, to_date ) - TRUNC( unit, from_date); compared to: In order to get the integer part of Impala's MONTHS_BETWEEN using Snowflake functions we apply the following logic : IFF(DAY(DATE1) >= DAY(DATE2), DATEDIFF('month', DATE2, DATE1), DATEDIFF('month', DATE2, DATE1) - 1) In order to get the fractional part of Impala's MONTHS_BETWEEN using Snowflake functions we apply the following logic : What is the best reusable way to calculate the total number of seconds that occurred on business days between two datetime values (ignoring weekends and federal holidays)? To calculate the difference between two timestamps, convert them to unix timestamps then subtract: Master date and time queries in Snowflake with our comprehensive guide. functions. Example: DATEDIFF on several events for specific value. Postgres doesn’t have DATEDIFF(). Ask Mike anything about becoming a Data Superhero, building ML models, his journey as a global nomad, and more! snowflake. Invalid function type [TIMEDIFF] for window function. I want the end result to be a date. Snowflake SQL Query - Invalid Argument Function Using DATEADD() Hot Network QuestionsSYSDATE¶. TO_TIME converting to LTZ. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) But based on my reading and some SQL Fiddle, it seems to output the start of "this week" minus 3 days. Any fields using concatenation likely need to be modified. snowflake. DATE_TRUNC. expr1 and expr2 are date or date-and-time expressions. I am struggling with a snowflake Database LEFT JOIN query with a date range. I have to compare 2 separate columns to come up with the most recent date between them. DATEDIFF (WEEK,. I have this piece of code that works in SQL server. The number of dateparts separating two date/time instances is too large You can use following method which is overflow-safe and gives you a float result:The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) Info: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. datediff ( part : str , col1 : Union [ Column , str ] , col2 : Union [ Column , str ] ) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the. There is no one-fit syntax for DATE formatting. Calculates the difference between two date, time, or timestamp expressions based on the specified date or time part. For more info, check out our list of common SQL reference guides. Written by Mike Diaz. October 10, 2023. AMA WITH MIKE TAVEIRNE Exciting news! Data Superhero, Mike Taveirne, is in forums from Sept 26-29 to answer your questions. SELECT DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) Best Regards, Joy. datediff¶ snowflake. The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. by date or location). modifiedon, GETDATE ()) = 0) But I need to select the yesterday. The reason I like to do it this way, is because its flexible enough that I can add weekly, hourly, or monthly intervals between the dates and reuse the code. Any suggestions? ,DATEDIFF(SECOND, DATETIME_1, DATETIME_2) AS DIFF_SECONDS. here is one. So the order should be always if deadline is NULL. As Lukasz points out the second parameter is the start_month SAP doc's. A more general form of the question is Snowflake takes the simpler approach, and answer all units of date_diff in the difference of the values at the unit compared. I'm having trouble getting it to run in snowflake. For ' integer ' (a string containing an integer), the integer is treated as a number of seconds, milliseconds, microseconds, or. Sorted by: 0. How to get difference betwen these below two dates in snowflake. Otherwise, the current session time zone is used. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. 'Datetime' is filetype DateTime in snowflake, but in SQL, it's just a date MM-DD-YYYY, so there is the 6:00 added to turn it into a datetime. so you would expect to only get two rows if you use this logic in the filter, which is what happens. functions. EXTRACT. 0. If you want to mimic hive logic in snowflake, you should use below code -. If the value is a non-integer numeric value (for example, FLOAT) the value will be rounded to the nearest integer. functions. functions. First, convert the text values (presumably) to valid datetime values. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. functions. I am not able to find the right solution for this. The function returns the result of. unable to understand the dateadd function in SQL. I can't make much changes to backend due to limited access. A function that could be interesting for Data Analysts and Data Scientists is the DATEDIFF function. Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO. g. Do not use the returned value for precise time ordering between concurrent queries. Commonly used datepart units include month or second. g. This allows, for example, choosing the N-th day in a year, which can be. Calculates the beginning or end of a “slice” of time, where the length of the slice is a multiple of a standard unit of time (minute, hour, day, etc. Based on Snowflake docs: Dynamically Creating a SQL Statement As stated in SQL Injection (in this topic), be careful to guard against attacks when using dynamic SQL. 5 * FLOOR ((DATEDIFF (day, date_trunc ('quarter', @s), @e)). Date_Time, Stack Overflow. functions. Applies to: Databricks SQL preview Databricks Runtime 11. Given the basic example,. For example: Truncating a timestamp down to the quarter returns the timestamp corresponding to midnight of the first day of the quarter for the input timestamp. DATEDIFF — Snowflake Documentation; PIVOT — Snowflake Documentation; I cannot seem to get pivot to work in SQL Snowflake (conditional aggregation), Stack Overflow; Pivot Tables. AWS Redshift vs Snowflake: A quick comparison. Thank you for your response. Some time you expect the diff in "days" between 1. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号（-）を使用して日付を減算することもできます。Truncates a DATE, TIME, or TIMESTAMP to the specified precision. In almost all cases, at least one of those expressions references a column in that row. Is there any inbuilt function that provides the timestamp instead of computing the datediff every time? In both cases above the output timestamp is epoch timestamp corresponding to the CURRENT_DATE (which is the. So I would return 0. SELECT DATEDIFF (DAY, xx, yy) AS Avg_DayDiff FROM Database1. If the input data type is DATE, and the date_or_time_part is hours or. Berechnet die Differenz zwischen zwei Datums-, Zeit- oder Zeitstempelausdrücken anhand der angeforderten Datums- oder Zeitkomponente. Found the solution -- I set a static value for the GENERATOR and then put a QUALIFY statement on it to limit the values to the first maxrange returned. datePart is the part of the date to return. array_aggJoin our community of data professionals to learn, connect, share and innovate together. To get the number of full time units passed between datetimes, you can calculate the difference in lower units and then divide by the appropriate number. date1 and date2 are the respective starting and ending dates for which you are about to find the difference. 함수 참조. Assuming that end_datetime and start_datetime are a datetime or timestamp field, you can just use the datediff() function:. date_or_time_part must be one of the values listed in Supported Date and Time Parts. Minute of the specified hour. The second step involves getting a difference in seconds between the two dates and converting that difference into hours by dividing by 3600. Thanks for help . Improve this answer. example, if start_date and end_date differed by 59 seconds, then DATEDIFF(MINUTE, start_date, end_date) / 60. Didn't know that. はじめに Snowflake の 日時（日付、時刻含む）について 少しづつだが、まとめておく。 目次 【1】日時（日付、時刻含む）のデータ型 【2】現在日時を返す関数 【3】日時（日付、時刻含む）の変換 1）キャスト 2）DATE_FROM_PARTS関数 【4】日時の計算 1）DATEADD関数 2）DATEDI…The date functions in Snowflake are same or slightly different compared to other RDBMS. I want to run the same code again with different parameters and want. I want to create Calendar Table in Snowflake which has start and end date as dynamic dates. The Snowflake INTERVAL functions are commonly used to manipulate date and time variables or expressions. 0. DATEADD () function is used to add the specified value for the specified date or time part to a date, time, or timestamp. 1. datediff. CUSTOMER_ID, C. We would like to show you a description here but the site won’t allow us. Here is an example Here is an example1. This works fine: SELECT. snowpark. SELECT AVG (CAST (DATEDIFF (d, DateUsed, DateExpires) AS FLOAT)) FORM tbl. Cognos will convert this to DATEDIFF but the arguments are reversed in the 2 functions. 00. Snowflake is a complete SaaS offering that requires no maintenance. Make sure that the data type of each column is consistent across the rows from different sources. 1239') は1. Query the GENERATOR function on the temporary table:Add a comment. Uses snowflake procedures to build and (daily)rollover of the the definition of current date, week, month etc. How to calculate the time difference in format hh:mm:ss. This is how I was able to generate a series of dates in Snowflake. Invalid function type [TIMEDIFF] for window function. 小数秒は丸められません。. If so, 20 business days is exactly 4 weeks, which is exactly 28 days. Note, that since DATEDIFF returns an integer value, the result also will be an integer. Many applications use date functions to manipulate the date and time data types. (datediff(DAY, uc. TIMEADD: Adds the specified value for the specified date. datediff¶ snowflake. Select (CASE when targetcompletedate <= NOW() the 'Overdue' else 'Days Left' end) If you want to show things as numbers, then you want the datediff(). Hour of the specified day. ,datediff(second, datetime_1, datetime_2) as diff_seconds ,diff_seconds % (60) as num_seconds ,floor(diff_seconds / 60) % 60 as num_minutes ,floor(diff_seconds /. Like Liked Unlike Reply. Grants_To_Users. BOO_DateCO)Hi @Mike Walton (Snowflake) , thanks for your answer. I consent to my information being shared with Event Partners in accordance with Snowflake’s Event. You can also use these to calculate age. In this article: Syntax. select t. columns WHERE table_name = 'hrStaff'. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. * from (select t. I'm trying to calculate an age value for our users based on their birthday, which one would expect to be a simple enough operation. TIMESTAMP_TZ. I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go. This allows you to ensure that the data changes made by the stored procedure are consistent and atomic. select distinct; p. 1 Answer. Creates rows of data based either on a specified number of rows, a specified generation period (in seconds), or both. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. nanosecond は、時、分、秒、および小数秒の9桁すべてを使用します. A window function is generally passed two parameters: A row. SELECT date_from ,date_to ,part ,case part when 'month' then datediff ('month', date_from, date_to) when 'day' then datediff ('day', date_from, date_to) when 'hour' then datediff ('hour', date_from, date_to). The datepart passed to DATEDIFF will control the resolution of the output. SQL Server : -- Get difference in days SELECT DATEDIFF ( dd, '2022-09-01', '2022-09-05'); # 4. Invalid function type [DATEDIFF] for window function. Join us at Snowflake Summit 2024 to explore all the cutting-edge innovation the Data Cloud has to offer. TIME_SLICE. You can't display more than 24 hours in a time format 00:00, so you need to choose a different way to display the output. sql; snowflake-cloud-data-platform;. select count(*) from orders. One of the examples in the Examples section below illustrates the. convert(varchar,cast((End_Datetime-Start_Datetime) as time),108) how to convert this to snowflake snowflake. From fetching the current timestamp to calculating date differences, we've got you covered. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. Then next new "min_date" = previous "next_date" until "DATEDIFF" is calculated. SQL; Snowflake; Timestamp +1 more; Like; Answer; Share; 1 answer; 1. The return value is always of type TIMESTAMP_TZ. event_id, evnt. functions. From fetching the current timestamp to calculating date differences, we've got you covered. An alternative sql only solution - start and end dates go into the current_date() spots. 0 to 59. for the first record, it must be calculated from 9am on 2021-05-19, hence the result would be 45 minutes. I can convert the TZ on the timestamps, but that's undone by the time-only functions. Alternative for DATEDIFF. Mar 27, 2013 at 14:06. Share. functions. DATEDIFF¶ Calcula a diferença entre duas expressões de data, hora ou carimbo de data/hora com base na parte de data ou hora solicitada. Usage Notes¶. I have a use case that I need to run a sql code snippet in a stored procedure, I saw this post and I didn't see how I can utilize my code using the suggested solution. Stack Overflow. functions. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. There are 3 different timestamp types in Snowflake: TIMESTAMP_NTZ is the datatype for timestamps without a timezone (ntz = no time zone). 000. Answer. DATEDIFF() is a function found in SQL Server and MySQL that calculates and returns the difference between two date values. 2 days. snowflake. You can only run them separately. With that, I expect that someone can provide you with a solution for you in Snowflake. More from Mike Diaz. Scaffolding your data can be the key to creating analyses such as the current number of open tickets on a given day or displaying the number. DECLARE @EndDate as date . I am trying to get the same output in Snowflake, but cant figure out how to return a float. Along with Preeti Shrimal, Adwate Kumar. This function comes in two flavours: MySQL 2 argument version. I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. 0 and 1. Modified 6 years, 9 months ago. Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. select post_visid_high || ':' || post_visid_low as visitor_id , lag (date_time) over (partition by visitor_id order by date_time asc) as previous_date , datediff (minute, previous_date, date_time) as difference_in_minutes from adobe_data. The setting of the TIMEZONE session parameter affects the return value. Account_Usage. TABLES WHERE TABLE_SCHEMA = 'REPORTING' AND TABLE_NAME ='LOGS' AND MINUTES_SINCE_LAST_UPDATE >. A general expression. Syntax For DATEDIFF DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) For minus sign <date_expr2> - <date_expr1> Arguments For DATEDIFF: date_or_time_part The unit of time. 非推奨の警告: Snowflakeの将来のバージョンでは、文字列化された整数値をミリ秒、マイクロ秒、ナノ秒ではなく、秒として自動的に解釈する可能性があります。. Supported date and time parts. Here are a few simple examples of using BETWEEN with numeric and string values:You can subtract days from a date in Snowflake using the DATEADD function. Result as Date — Image by Author Function 3: Date Difference. Converts an input expression to a date: For a string expression, the result of converting the string to a date. There are certain use case scenarios when it is recommended to use the CURRENT_DATE function within the Snowflake cloud data warehouse which are as follows: You want to match the current date with column value to get the required output. Deleted my comment to avoid confusing anyone. An image can help us visualize the concept you have, but the code is what you're trying to fix. date, DATEDIFF ('day', first_action. It assumes that two given dates are business days. 5 to 0), pass in 'HALF_TO_EVEN' for the rounding_mode argument. Thanks, Rag. For the second record, it. DATETIME is an alias for TIMESTAMP_NTZ. This value is returned if the condition is true. What is the difference between Snowflake DATEDIFF() and DATEADD()? Snowflake DATEDIFF() calculates the difference between two dates, while DATEADD(). 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号（-）を使用して日付を減算することもできます。If the datasource was previously pointing to SQL Server or DB2 and is now going to Snowflake, there might be some incorrect results when using the days_between. I 引数¶ date_or_time_part. functions. How to write following query in snowflake. Search for "Calendars for Finance and Analytics". snowpark. functions. It may be positive or negative. Expand Post. If you are using SQL Server 2012 or higher version,Try with the below script. Thanks! Expand Post. I would use this: DECLARE @BegDate as date. datepart The units in which DATEDIFF reports the difference between the startdate and enddate. This topic describes how to use the different types of window functions supported by Snowflake, including: General window functions. month ). To comply with ANSI standards, this function can be called without parentheses. Calculates the difference between two date, time, or timestamp expressions based on the specified date or time part. insertedon,1,10))) There is any simple way to do this? just a subtraction of 2 hours to date time Regards. これは、追加する時間単位を示します。例えば、2日を追加する場合、これは DAY になります。 この測定単位は、 サポートされている日付と時刻の部分 にリストされている値のいずれかでなければなりません。 For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. One way to do this is by creating a working hours table. Then you can run a fairly simple query: select t. DATEDIFF(hh, GETUTCDATE(),. DECLARE @Date0 date = '2016-04-07'; -- Thursday. functions. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. Hi @SQL Baby , Last Day of previous month：. In the first form of CASE, each condition is an expression that should evaluate to a BOOLEAN value (True, False, or NULL). Window functions that calculate rank (e.